Date:03 Mar 98 03:12:50From:mweber@t140.aone.net.au (James Matthew Weber)Organization:GoodNetReferences:1 2Followups:1

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On 19 Feb 98 01:34:26 , Chris Pitzel <chris.pitzel@usask.ca> wrote: >If you were to measure your weight on an aircraft at FL400 and your >weight at sea level, you would find that you would weigh less at >altitude. For example, I weigh roughly 130 pounds at sea level, yet I >would only weigh perhaps 110 pounds at 40k feet. There are formulas to >determine this which can be derived from the relationship: > > F = G*m1*m2/r^2 The reduction in F is trivial, in fact the radius of the earth is substantally higher at the equator than it is at the poles, far more than the mere 8 miles that 40,000 feet represents. The difference in weight between sea level and 40,000 feet . If you take the radius of the earth to be about 4000 miles, you can work out that the differerence in F is about .2%. Your 130 pounds at sea level will weight 129.7 pounds at 40,000 feet. This is simply not a significant factor.